Solving Linear Inequalities

Work with ranges of solutions instead of single answers

If you have already solved linear equations, you are more than ready for inequalities. Think of inequalities as equations’ more flexible cousin. Instead of asking “what single value makes this true?” inequalities ask “what range of values works?” This is actually more realistic for many real-world situations. After all, how often does a budget constraint require you to spend exactly $50? More likely, you need to spend at most $50 or at least $20. That is where inequalities come in.

Core Concepts

What is an Inequality?

An inequality is a mathematical statement comparing two expressions where one side is not necessarily equal to the other. Instead of the equals sign ($=$), we use inequality symbols to show the relationship.

For example:

  • $x < 5$ means “$x$ is less than 5”
  • $x > 3$ means “$x$ is greater than 3”
  • $x \leq 7$ means “$x$ is less than or equal to 7”
  • $x \geq -2$ means “$x$ is greater than or equal to $-2$”

The key difference from equations: while $x + 3 = 7$ has exactly one solution ($x = 4$), the inequality $x + 3 < 7$ has infinitely many solutions. Any number less than 4 works: 3, 2, 0, -100, 3.999, and countless others.

Understanding Inequality Symbols

Here is a helpful way to remember the symbols: the inequality sign always “points to” the smaller value. You can think of it as an alligator mouth that wants to eat the bigger number.

  • $3 < 5$ — The “mouth” opens toward 5 because 5 is bigger
  • $10 > 2$ — The “mouth” opens toward 10 because 10 is bigger

The symbols $\leq$ and $\geq$ include the possibility of equality. So $x \leq 5$ means $x$ can be 5, or it can be anything smaller than 5.

The symbol $\neq$ simply means “not equal to.” So $x \neq 0$ tells us that $x$ can be any number except zero.

Graphing Inequalities on a Number Line

Since inequalities have infinitely many solutions, we cannot list them all. Instead, we visualize them on a number line.

For $x < 4$:

<-------|-------|-------|---○========>
        1       2       3   4       5
  • Open circle at 4 (because 4 itself is not included)
  • Shade to the left (all numbers less than 4)

For $x \geq -1$:

<======|---●========|=======>
      -2  -1        0       1
  • Closed circle at $-1$ (because $-1$ is included)
  • Shade to the right (all numbers $-1$ or greater)

The rule for circles:

  • Use an open circle ($\circ$) for $<$ or $>$ — the endpoint is NOT included
  • Use a closed circle ($\bullet$) for $\leq$ or $\geq$ — the endpoint IS included

Solving One-Step Inequalities

Here is the good news: solving inequalities works almost exactly like solving equations. You use the same inverse operations to isolate the variable.

Addition/Subtraction: No special rules needed.

If $x + 5 > 12$, subtract 5 from both sides: $$x + 5 - 5 > 12 - 5$$ $$x > 7$$

If $x - 3 \leq 10$, add 3 to both sides: $$x - 3 + 3 \leq 10 + 3$$ $$x \leq 13$$

Multiplication/Division by positive numbers: No special rules needed.

If $4x < 20$, divide both sides by 4: $$\frac{4x}{4} < \frac{20}{4}$$ $$x < 5$$

The Flip Rule: Multiplying or Dividing by Negatives

Here is where inequalities differ from equations, and this is crucial: when you multiply or divide both sides of an inequality by a negative number, you must flip (reverse) the inequality sign.

Why? Consider this: we know $3 < 5$. But if we multiply both sides by $-1$:

  • $-1 \times 3 = -3$
  • $-1 \times 5 = -5$

Is $-3 < -5$? No! On the number line, $-3$ is to the right of $-5$, so $-3 > -5$.

Multiplying by a negative number reverses the order of numbers. That is why we flip the sign.

Example: Solve $-2x \leq 8$.

Divide both sides by $-2$. Since we are dividing by a negative, flip the sign: $$\frac{-2x}{-2} \geq \frac{8}{-2}$$ $$x \geq -4$$

Common mistake alert: Many students forget to flip the sign when dividing by a negative. Always pause and ask yourself: “Am I multiplying or dividing by a negative number?” If yes, flip the inequality symbol.

Solving Multi-Step Inequalities

Just like multi-step equations, some inequalities require more than one operation. The strategy is the same: use inverse operations in the reverse order (undo addition/subtraction first, then undo multiplication/division).

Example: Solve $3x - 5 < 10$.

Step 1: Add 5 to both sides. $$3x - 5 + 5 < 10 + 5$$ $$3x < 15$$

Step 2: Divide both sides by 3. $$\frac{3x}{3} < \frac{15}{3}$$ $$x < 5$$

The solution is all numbers less than 5.

Compound Inequalities

Sometimes we need to express that a value falls within a certain range. That is where compound inequalities come in. There are two types:

AND compound inequalities (the value must satisfy BOTH conditions):

$-2 < x \leq 5$ means $x$ is greater than $-2$ AND less than or equal to 5.

This can also be written as two separate inequalities:

  • $x > -2$ AND $x \leq 5$

On a number line, the solution is the overlap of both conditions:

<---○===========●----->
   -2    0      5

OR compound inequalities (the value must satisfy AT LEAST ONE condition):

$x < -1$ OR $x \geq 3$ means $x$ is either less than $-1$ or greater than or equal to 3.

On a number line, the solution includes BOTH regions:

<====○---|---○===●====>
    -1   0   2   3

Solving compound inequalities:

For AND inequalities written in compact form like $-4 < 2x + 2 \leq 10$, you can solve by performing the same operation on all three parts:

Step 1: Subtract 2 from all three parts. $$-4 - 2 < 2x + 2 - 2 \leq 10 - 2$$ $$-6 < 2x \leq 8$$

Step 2: Divide all three parts by 2. $$\frac{-6}{2} < \frac{2x}{2} \leq \frac{8}{2}$$ $$-3 < x \leq 4$$

For OR inequalities, solve each inequality separately and combine the solutions.

Interval Notation

Mathematicians often use a compact notation called interval notation to describe solution sets.

Inequality Interval Notation Meaning
$x > 3$ $(3, \infty)$ All numbers greater than 3
$x \geq 3$ $[3, \infty)$ All numbers 3 or greater
$x < 5$ $(-\infty, 5)$ All numbers less than 5
$x \leq 5$ $(-\infty, 5]$ All numbers 5 or less
$-2 < x \leq 5$ $(-2, 5]$ Between $-2$ and 5, including 5
$x < -1$ or $x \geq 3$ $(-\infty, -1) \cup [3, \infty)$ Less than $-1$ OR 3 or greater

Key rules:

  • Use ( or ) (parentheses) when the endpoint is NOT included
  • Use [ or ] (brackets) when the endpoint IS included
  • Always use parentheses with $\infty$ and $-\infty$ (infinity is not a number you can reach)
  • The symbol $\cup$ means “union” or “OR” — it combines separate intervals

Notation and Terminology

Term Meaning Example
$<$ Less than $x < 5$
$>$ Greater than $x > 3$
$\leq$ Less than or equal to $x \leq 7$
$\geq$ Greater than or equal to $x \geq -2$
Solution set All values satisfying inequality ${x \mid x > 3}$
Compound inequality Two inequalities combined $-2 < x \leq 5$
Interval notation Another way to write solution sets $(-2, 5]$

Examples

Example 1: Solve and Graph $x + 3 > 7$

Solution:

The variable $x$ has 3 added to it. To isolate $x$, subtract 3 from both sides.

$$x + 3 - 3 > 7 - 3$$ $$x > 4$$

Graph:

<-------|-------|-------|---○========>
        2       3       4   5       6

Open circle at 4 (not included), shading to the right.

In interval notation: $(4, \infty)$

Check: Pick a number greater than 4, say $x = 5$. Does $5 + 3 > 7$? Yes, $8 > 7$ is true.

Real-world connection: You need more than $7 to buy lunch. You already have $3 in coins. How much more do you need? Any amount greater than $4.

Example 2: Solve $-2x \leq 8$ (The Flip Rule)

Solution:

The variable $x$ is being multiplied by $-2$. To isolate $x$, divide both sides by $-2$.

Important: Since we are dividing by a negative number, we must flip the inequality sign!

$$\frac{-2x}{-2} \geq \frac{8}{-2}$$ $$x \geq -4$$

Graph:

<====|---●========|=======>
    -5  -4       -3      -2

Closed circle at $-4$ (included), shading to the right.

In interval notation: $[-4, \infty)$

Check: Pick a number $\geq -4$, say $x = 0$. Does $-2(0) \leq 8$? Yes, $0 \leq 8$ is true.

Also check a boundary case: $x = -4$. Does $-2(-4) \leq 8$? Yes, $8 \leq 8$ is true (equality is allowed).

Why the flip matters: If we had forgotten to flip, we would have gotten $x \leq -4$, which is wrong. Testing $x = -5$ (which would be in that solution set): $-2(-5) = 10$, and $10 \leq 8$ is false!

Example 3: Solve $3x - 5 < 10$

Solution:

This is a two-step inequality. Work in reverse order of operations.

Step 1: Add 5 to both sides (undo the subtraction first). $$3x - 5 + 5 < 10 + 5$$ $$3x < 15$$

Step 2: Divide both sides by 3 (undo the multiplication). $$\frac{3x}{3} < \frac{15}{3}$$ $$x < 5$$

Graph:

<-------|-------|-------|---○========>
        2       3       4   5       6

Open circle at 5, shading to the left.

In interval notation: $(-\infty, 5)$

Check: Pick $x = 2$. Does $3(2) - 5 < 10$? We get $6 - 5 = 1$, and $1 < 10$ is true.

Real-world connection: A streaming service costs $5 per month plus $3 per movie rented. If you want to spend less than $10 this month, how many movies can you rent? Fewer than 5 movies (so 0, 1, 2, 3, or 4 movies).

Example 4: Solve and Graph $-4 < 2x + 2 \leq 10$

Solution:

This is a compound AND inequality. We need to isolate $x$ in the middle by performing operations on all three parts.

Step 1: Subtract 2 from all three parts. $$-4 - 2 < 2x + 2 - 2 \leq 10 - 2$$ $$-6 < 2x \leq 8$$

Step 2: Divide all three parts by 2. $$\frac{-6}{2} < \frac{2x}{2} \leq \frac{8}{2}$$ $$-3 < x \leq 4$$

Interpretation: $x$ is greater than $-3$ AND less than or equal to 4.

Graph:

<---○===============●--->
   -3  -1   0   2   4   6

Open circle at $-3$ (not included), closed circle at 4 (included), shading between them.

In interval notation: $(-3, 4]$

Check: Pick $x = 0$ (in the solution set). Does $-4 < 2(0) + 2 \leq 10$? We get $-4 < 2 \leq 10$, which is true.

Check a boundary: $x = 4$. Does $-4 < 2(4) + 2 \leq 10$? We get $-4 < 10 \leq 10$, which is true.

Check outside the boundary: $x = -3$. Does $-4 < 2(-3) + 2 \leq 10$? We get $-4 < -4 \leq 10$, and $-4 < -4$ is false. So $-3$ is correctly not included.

Real-world connection: A safe operating temperature for a device is between $-4$ and $10$ degrees Celsius, where $10$ degrees is the upper limit. If the display shows $2x + 2$ degrees (due to a calibration offset), what raw sensor values $x$ are safe?

Example 5: Solve $2x - 1 > 5$ OR $3x + 4 < -2$

Solution:

This is a compound OR inequality. Solve each inequality separately, then combine the solutions.

First inequality: $2x - 1 > 5$

Add 1 to both sides: $$2x - 1 + 1 > 5 + 1$$ $$2x > 6$$

Divide both sides by 2: $$x > 3$$

Second inequality: $3x + 4 < -2$

Subtract 4 from both sides: $$3x + 4 - 4 < -2 - 4$$ $$3x < -6$$

Divide both sides by 3: $$x < -2$$

Combined solution: $x > 3$ OR $x < -2$

Interpretation: Any number greater than 3 works, OR any number less than $-2$ works. Numbers between $-2$ and 3 (inclusive) do not satisfy either condition.

Graph:

<====○---|-------|---○====>
    -2   0       2   3   5

Two separate regions with open circles at both $-2$ and 3.

In interval notation: $(-\infty, -2) \cup (3, \infty)$

Check:

  • Pick $x = 5$ (in the right region). First inequality: $2(5) - 1 = 9$, and $9 > 5$ is true. (Only one needs to be true for OR.)
  • Pick $x = -4$ (in the left region). Second inequality: $3(-4) + 4 = -8$, and $-8 < -2$ is true.
  • Pick $x = 0$ (between the regions). First: $2(0) - 1 = -1$, and $-1 > 5$ is false. Second: $3(0) + 4 = 4$, and $4 < -2$ is false. Neither is true, so 0 is not a solution.

Real-world connection: A factory machine triggers an alarm if the pressure reading is above 5 psi OR below $-2$ psi (indicating a vacuum leak). If the gauge shows $2x - 1$ psi in one mode or $3x + 4$ psi in another mode, for what raw sensor values $x$ will the alarm sound?

Key Properties and Rules

The Basic Principle

Solving inequalities follows the same logic as solving equations: use inverse operations to isolate the variable. Whatever you do to one side, do to the other.

The Critical Exception: The Flip Rule

When you multiply or divide both sides of an inequality by a negative number, you must reverse (flip) the inequality sign.

$$-x > 5 \implies x < -5$$ $$\frac{x}{-2} \leq 3 \implies x \geq -6$$

Compound Inequalities

AND: The solution must satisfy both conditions. The final solution is the overlap (intersection) of both solution sets.

OR: The solution must satisfy at least one condition. The final solution is the combination (union) of both solution sets.

Graphing Guide

Symbol Circle Direction
$x < a$ Open at $a$ Shade left
$x > a$ Open at $a$ Shade right
$x \leq a$ Closed at $a$ Shade left
$x \geq a$ Closed at $a$ Shade right

Interval Notation Quick Reference

  • $($ or $)$ means NOT included
  • $[$ or $]$ means included
  • Always use $($ $)$ with $\infty$ and $-\infty$
  • Use $\cup$ to combine separate intervals (for OR)

Real-World Applications

Budget Constraints

You have a budget of at most $100 for groceries. If you have already spent $35, how much more can you spend?

Let $x$ = additional spending. $$35 + x \leq 100$$ $$x \leq 65$$

You can spend up to $65 more.

Height and Age Requirements

A roller coaster requires riders to be at least 48 inches tall.

If $h$ = height in inches: $$h \geq 48$$

Anyone 48 inches or taller can ride.

Temperature Ranges for Safety

A medication must be stored between 36 and 46 degrees Fahrenheit (inclusive) to remain effective.

If $T$ = temperature: $$36 \leq T \leq 46$$

In interval notation: $[36, 46]$

Grade Boundaries

To pass a class, you need an average of at least 60%. After four tests with scores of 55, 70, 58, and 62, what do you need on the fifth test?

Let $x$ = fifth test score. $$\frac{55 + 70 + 58 + 62 + x}{5} \geq 60$$ $$\frac{245 + x}{5} \geq 60$$ $$245 + x \geq 300$$ $$x \geq 55$$

You need at least 55% on the fifth test to pass.

Speed Limits

A highway has a minimum speed of 45 mph and a maximum of 70 mph.

If $s$ = your speed: $$45 \leq s \leq 70$$

Driving 40 mph or 75 mph would both be violations.

Self-Test Problems

Problem 1: Solve and graph $x - 4 \geq 3$.

Show Answer

Add 4 to both sides: $$x - 4 + 4 \geq 3 + 4$$ $$x \geq 7$$

Graph: Closed circle at 7, shade to the right.

In interval notation: $[7, \infty)$

Problem 2: Solve $-5x > 15$. (Remember the flip rule!)

Show Answer

Divide both sides by $-5$. Since we are dividing by a negative, flip the sign: $$\frac{-5x}{-5} < \frac{15}{-5}$$ $$x < -3$$

In interval notation: $(-\infty, -3)$

Check: Try $x = -4$. Does $-5(-4) > 15$? Yes, $20 > 15$ is true.

Problem 3: Solve $2x + 7 \leq 19$.

Show Answer

Step 1: Subtract 7 from both sides. $$2x + 7 - 7 \leq 19 - 7$$ $$2x \leq 12$$

Step 2: Divide both sides by 2. $$x \leq 6$$

In interval notation: $(-\infty, 6]$

Problem 4: Solve $1 \leq 3x - 2 < 10$.

Show Answer

Step 1: Add 2 to all three parts. $$1 + 2 \leq 3x - 2 + 2 < 10 + 2$$ $$3 \leq 3x < 12$$

Step 2: Divide all three parts by 3. $$1 \leq x < 4$$

Graph: Closed circle at 1, open circle at 4, shade between.

In interval notation: $[1, 4)$

Problem 5: Solve $x + 2 < 0$ OR $2x \geq 10$.

Show Answer

First inequality: $x + 2 < 0$ $$x < -2$$

Second inequality: $2x \geq 10$ $$x \geq 5$$

Combined solution: $x < -2$ OR $x \geq 5$

In interval notation: $(-\infty, -2) \cup [5, \infty)$

Problem 6: Write the solution $x > -3$ in interval notation.

Show Answer

$(-3, \infty)$

Parenthesis at $-3$ because it is not included; parenthesis at infinity because infinity is never included.

Problem 7: A taxi charges $3 plus $2 per mile. You have at most $15 to spend. How far can you travel?

Show Answer

Let $m$ = miles traveled. $$3 + 2m \leq 15$$ $$2m \leq 12$$ $$m \leq 6$$

You can travel at most 6 miles.

Summary

  • An inequality compares values using $<$, $>$, $\leq$, $\geq$, or $\neq$ instead of $=$.
  • Unlike equations with one solution, inequalities typically have infinitely many solutions (a range of values).
  • Solve inequalities using the same inverse operations as equations: undo addition/subtraction first, then undo multiplication/division.
  • The flip rule is critical: when multiplying or dividing by a negative number, reverse the inequality sign.
  • Graph inequalities on a number line using open circles ($<$, $>$) or closed circles ($\leq$, $\geq$).
  • Compound inequalities combine two conditions with AND (both must be true) or OR (at least one must be true).
  • Interval notation provides a compact way to write solution sets using parentheses for excluded endpoints and brackets for included endpoints.
  • Always check your solution by testing a value from your solution set in the original inequality.
  • Inequalities model many real-world situations involving constraints, requirements, and acceptable ranges.