Right Triangles and the Pythagorean Theorem
The most famous theorem in mathematics
There is a good chance you have heard of the Pythagorean Theorem before, even if math is not your favorite subject. It shows up everywhere: in construction, navigation, video games, architecture, and even in measuring your television screen. This single relationship between the sides of a right triangle has been known for over 2,500 years, and people still use it every single day. Whether a carpenter is checking that a wall is perfectly square or a pilot is calculating the shortest flight path, the Pythagorean Theorem is quietly doing the work behind the scenes.
The beautiful thing about this theorem is how simple it is to state, yet how powerful it is in practice. Once you understand it, you will start noticing right triangles everywhere, and you will have the tools to work with them confidently.
Core Concepts
What Makes a Triangle “Right”?
A right triangle is simply a triangle that has one angle measuring exactly $90°$, a right angle. That is the corner you see on a piece of paper, a door frame, or the edges of your phone screen. The presence of this right angle gives the triangle special properties that do not apply to other triangles.
The two sides that form the right angle are called the legs of the triangle. These are often labeled $a$ and $b$. The side opposite the right angle, the one that does not touch the right angle at all, is called the hypotenuse. The hypotenuse is always the longest side of a right triangle, and it is typically labeled $c$.
Here is an easy way to remember: the hypotenuse is “across” from the right angle. It is never one of the sides that forms the $90°$ corner.
The Pythagorean Theorem
Now for the main event. The Pythagorean Theorem tells us that in any right triangle, there is a precise relationship between the three sides:
$$a^2 + b^2 = c^2$$
In words: if you square the length of each leg and add those squares together, you get exactly the square of the hypotenuse.
This is not just approximately true or usually true. It is exactly true for every right triangle that has ever existed or ever will exist. The ancient Babylonians knew this relationship over 4,000 years ago. The Greek mathematician Pythagoras (or his followers) gets the credit for providing a formal proof, which is why we call it the Pythagorean Theorem.
Why does this matter? Because if you know any two sides of a right triangle, you can always find the third. This is incredibly useful in countless real-world situations.
Pythagorean Triples
Some right triangles have the special property that all three sides are whole numbers. These sets of three integers that satisfy $a^2 + b^2 = c^2$ are called Pythagorean triples.
The most famous is 3-4-5. Let us check: $3^2 + 4^2 = 9 + 16 = 25 = 5^2$. It works!
Here are some other common Pythagorean triples worth memorizing:
- 3, 4, 5: The classic. Carpenters love this one.
- 5, 12, 13: Another common one. Check: $25 + 144 = 169 = 13^2$.
- 8, 15, 17: Check: $64 + 225 = 289 = 17^2$.
- 7, 24, 25: Check: $49 + 576 = 625 = 25^2$.
Here is a useful fact: if you multiply all three numbers in a Pythagorean triple by the same value, you get another Pythagorean triple. For example, since 3-4-5 works, so does 6-8-10 (multiply by 2), and 9-12-15 (multiply by 3), and 30-40-50 (multiply by 10). This is why the 3-4-5 triple is especially handy; it scales to any size you need.
The Converse of the Pythagorean Theorem
The Pythagorean Theorem works in reverse, too. If you have a triangle and want to know whether it is a right triangle, just check whether $a^2 + b^2 = c^2$ (where $c$ is the longest side).
The Converse of the Pythagorean Theorem: If the sides of a triangle satisfy $a^2 + b^2 = c^2$, then the triangle is a right triangle, with the right angle opposite the longest side $c$.
This is incredibly useful for checking whether corners are “square” in construction or verifying that a shape has a right angle.
Classifying Triangles by Their Angles
The relationship between the sides can actually tell you what type of triangle you have:
- If $a^2 + b^2 = c^2$: The triangle is right (has a $90°$ angle)
- If $a^2 + b^2 > c^2$: The triangle is acute (all angles less than $90°$)
- If $a^2 + b^2 < c^2$: The triangle is obtuse (has an angle greater than $90°$)
Think of it this way: in a right triangle, the two shorter sides are “just right” to satisfy the equation. If those sides are “too big” (their squares sum to more than $c^2$), the angle opposite $c$ gets squeezed smaller than $90°$, making the triangle acute. If those sides are “too small,” the angle opposite $c$ opens up beyond $90°$, making the triangle obtuse.
Geometric Mean
Before we dive into special right triangles, there is one more concept that connects nicely with right triangles: the geometric mean.
The geometric mean of two positive numbers $a$ and $b$ is $\sqrt{ab}$.
Why does this matter for right triangles? When you draw the altitude (height) from the right angle to the hypotenuse in a right triangle, you create smaller triangles with some beautiful relationships:
- The altitude is the geometric mean of the two segments it creates on the hypotenuse.
- Each leg is the geometric mean of the hypotenuse and the segment of the hypotenuse adjacent to that leg.
These relationships are useful in more advanced problems and help explain why certain constructions work the way they do.
Special Right Triangles: 45-45-90
Some right triangles show up so often that they have their own names based on their angles. The first is the 45-45-90 triangle, also called an isosceles right triangle because the two legs are equal.
In a 45-45-90 triangle:
- The two legs are equal (both are some length $x$)
- The hypotenuse is $x\sqrt{2}$
$$\text{Legs: } x, x \qquad \text{Hypotenuse: } x\sqrt{2}$$
Where does $\sqrt{2}$ come from? Use the Pythagorean Theorem: if both legs are $x$, then $x^2 + x^2 = c^2$, which gives $2x^2 = c^2$, so $c = x\sqrt{2}$.
Think of it this way: the diagonal of a square is always $\sqrt{2}$ times the length of a side. If you cut a square in half diagonally, you get two 45-45-90 triangles.
Special Right Triangles: 30-60-90
The other special right triangle is the 30-60-90 triangle. This one comes from cutting an equilateral triangle in half.
In a 30-60-90 triangle:
- The side opposite the $30°$ angle (shortest leg) is $x$
- The side opposite the $60°$ angle (longer leg) is $x\sqrt{3}$
- The hypotenuse (opposite the $90°$ angle) is $2x$
$$\text{Shortest leg: } x \qquad \text{Longer leg: } x\sqrt{3} \qquad \text{Hypotenuse: } 2x$$
The ratio is always $1 : \sqrt{3} : 2$.
Here is why: start with an equilateral triangle where all sides have length $2x$. Draw the altitude from one vertex to the opposite side. This altitude bisects the opposite side (splitting it into two segments of length $x$) and bisects the vertex angle (creating two $30°$ angles). You now have two 30-60-90 triangles.
The altitude has length $x\sqrt{3}$ because by the Pythagorean Theorem: $(x)^2 + (\text{altitude})^2 = (2x)^2$, so $x^2 + (\text{altitude})^2 = 4x^2$, giving $(\text{altitude})^2 = 3x^2$, and altitude $= x\sqrt{3}$.
Notation and Terminology
| Term | Meaning | Example |
|---|---|---|
| Right triangle | Triangle with one $90°$ angle | The corner of a book |
| Legs | The two sides that form the right angle | $a$ and $b$ in $a^2 + b^2 = c^2$ |
| Hypotenuse | Side opposite the right angle (longest side) | $c$ in $a^2 + b^2 = c^2$ |
| Pythagorean triple | Three integers satisfying $a^2 + b^2 = c^2$ | 3, 4, 5 or 5, 12, 13 |
| Converse | The “reverse” statement of a theorem | If $a^2 + b^2 = c^2$, then right triangle |
| Acute triangle | All angles less than $90°$ | Satisfied when $a^2 + b^2 > c^2$ |
| Obtuse triangle | Has one angle greater than $90°$ | Satisfied when $a^2 + b^2 < c^2$ |
| Geometric mean | $\sqrt{ab}$ for two numbers $a$ and $b$ | Geometric mean of 4 and 9 is 6 |
| 45-45-90 | Isosceles right triangle | Sides: $x$, $x$, $x\sqrt{2}$ |
| 30-60-90 | Half of an equilateral triangle | Sides: $x$, $x\sqrt{3}$, $2x$ |
Examples
A right triangle has legs measuring 6 cm and 8 cm. Find the length of the hypotenuse.
Solution:
We know both legs, and we need the hypotenuse. Use the Pythagorean Theorem: $$a^2 + b^2 = c^2$$
Substitute the known values: $$6^2 + 8^2 = c^2$$ $$36 + 64 = c^2$$ $$100 = c^2$$
Take the square root of both sides: $$c = \sqrt{100} = 10 \text{ cm}$$
Notice that 6-8-10 is just the 3-4-5 triple multiplied by 2!
A right triangle has a hypotenuse of 13 inches and one leg of 5 inches. Find the other leg.
Solution:
This time we know the hypotenuse and one leg. Let the unknown leg be $a$: $$a^2 + b^2 = c^2$$ $$a^2 + 5^2 = 13^2$$ $$a^2 + 25 = 169$$
Subtract 25 from both sides: $$a^2 = 144$$
Take the square root: $$a = \sqrt{144} = 12 \text{ inches}$$
This is the 5-12-13 Pythagorean triple.
A triangle has sides of length 7, 9, and 11. Is this triangle right, acute, or obtuse?
Solution:
First, identify the longest side: 11. This would be the hypotenuse if the triangle were right.
Calculate $a^2 + b^2$ where $a$ and $b$ are the two shorter sides: $$7^2 + 9^2 = 49 + 81 = 130$$
Calculate $c^2$ where $c$ is the longest side: $$11^2 = 121$$
Compare:
- $a^2 + b^2 = 130$
- $c^2 = 121$
Since $130 > 121$, we have $a^2 + b^2 > c^2$.
This means the triangle is acute (all angles less than $90°$).
The sum of the squares of the shorter sides is “too big” for the triangle to be right, which means the angle opposite the longest side is squeezed smaller than $90°$.
In a 45-45-90 triangle, the hypotenuse is 10 units. Find the length of each leg.
Solution:
In a 45-45-90 triangle, the sides follow the pattern: $$\text{Leg: } x \qquad \text{Leg: } x \qquad \text{Hypotenuse: } x\sqrt{2}$$
We know the hypotenuse is 10, so: $$x\sqrt{2} = 10$$
Solve for $x$: $$x = \frac{10}{\sqrt{2}}$$
Rationalize the denominator (multiply top and bottom by $\sqrt{2}$): $$x = \frac{10}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{10\sqrt{2}}{2} = 5\sqrt{2}$$
Each leg is $5\sqrt{2}$ units, which is approximately $5 \times 1.414 = 7.07$ units.
Check: $(5\sqrt{2})^2 + (5\sqrt{2})^2 = 50 + 50 = 100 = 10^2$. It works!
In a 30-60-90 triangle, the side opposite the $60°$ angle measures $9\sqrt{3}$ units. Find the lengths of the other two sides.
Solution:
In a 30-60-90 triangle, the sides follow the pattern: $$\text{Opposite } 30°: x \qquad \text{Opposite } 60°: x\sqrt{3} \qquad \text{Hypotenuse: } 2x$$
We are told the side opposite $60°$ is $9\sqrt{3}$: $$x\sqrt{3} = 9\sqrt{3}$$
Divide both sides by $\sqrt{3}$: $$x = 9$$
Now find the other sides:
- Side opposite $30°$ (shorter leg): $x = 9$ units
- Hypotenuse: $2x = 2(9) = 18$ units
Check using the Pythagorean Theorem: $$9^2 + (9\sqrt{3})^2 = 81 + 81(3) = 81 + 243 = 324 = 18^2$$
It checks out!
A ladder leans against a wall, making a $60°$ angle with the ground. The foot of the ladder is 5 feet from the base of the wall. How long is the ladder, and how high up the wall does it reach?
Solution:
When the ladder makes a $60°$ angle with the ground, it creates a 30-60-90 triangle (since the wall and ground form a $90°$ angle, and $90° + 60° = 150°$, leaving $180° - 150° = 30°$ for the top angle).
In this setup:
- The $60°$ angle is at the base (where ladder meets ground)
- The $30°$ angle is at the top (where ladder meets wall)
- The $90°$ angle is where the wall meets the ground
- The 5-foot distance (foot of ladder to wall) is opposite the $30°$ angle
In a 30-60-90 triangle with pattern $x : x\sqrt{3} : 2x$:
- Side opposite $30°$ = $x$ = 5 feet
- Side opposite $60°$ = $x\sqrt{3}$ (height on wall)
- Hypotenuse = $2x$ (ladder length)
So: $$x = 5$$
Ladder length: $2x = 2(5) = 10$ feet
Height on wall: $x\sqrt{3} = 5\sqrt{3} \approx 5 \times 1.732 = 8.66$ feet
The ladder is 10 feet long and reaches approximately 8.66 feet up the wall.
Check: $5^2 + (5\sqrt{3})^2 = 25 + 75 = 100 = 10^2$. Confirmed!
Key Properties and Rules
The Pythagorean Theorem and Its Converse
Pythagorean Theorem: In a right triangle with legs $a$ and $b$ and hypotenuse $c$: $$a^2 + b^2 = c^2$$
Converse: If three sides of a triangle satisfy $a^2 + b^2 = c^2$ (where $c$ is the longest), then the triangle is a right triangle.
Triangle Classification by Sides
For a triangle with sides $a$, $b$, and $c$ (where $c$ is the longest):
$$a^2 + b^2 = c^2 \implies \text{Right triangle}$$ $$a^2 + b^2 > c^2 \implies \text{Acute triangle}$$ $$a^2 + b^2 < c^2 \implies \text{Obtuse triangle}$$
Common Pythagorean Triples
| Triple | Verification |
|---|---|
| 3, 4, 5 | $9 + 16 = 25$ |
| 5, 12, 13 | $25 + 144 = 169$ |
| 8, 15, 17 | $64 + 225 = 289$ |
| 7, 24, 25 | $49 + 576 = 625$ |
Scaling rule: Multiply any triple by $k$ to get another valid triple: $ka$, $kb$, $kc$.
Special Right Triangle Ratios
45-45-90 Triangle: $$x : x : x\sqrt{2}$$
- Legs are equal
- Hypotenuse = leg $\times \sqrt{2}$
- Leg = hypotenuse $\div \sqrt{2}$ = hypotenuse $\times \frac{\sqrt{2}}{2}$
30-60-90 Triangle: $$x : x\sqrt{3} : 2x$$
- Shortest leg (opposite $30°$) = $x$
- Longer leg (opposite $60°$) = $x\sqrt{3}$
- Hypotenuse (opposite $90°$) = $2x$
- Hypotenuse is always twice the shortest leg
Geometric Mean Relationships
In a right triangle with altitude $h$ drawn to hypotenuse $c$, which creates segments $p$ and $q$ on the hypotenuse:
$$h = \sqrt{pq}$$
$$a = \sqrt{cp} \quad \text{and} \quad b = \sqrt{cq}$$
where $a$ is the leg adjacent to segment $p$ and $b$ is the leg adjacent to segment $q$.
Real-World Applications
Construction: Checking for Square Corners
Carpenters and builders use the 3-4-5 rule constantly. To check if a corner is square:
- Measure 3 feet along one edge from the corner
- Measure 4 feet along the other edge from the corner
- The diagonal between these two points should be exactly 5 feet
If the diagonal is exactly 5 feet, the corner is a perfect $90°$ angle. If not, the corner needs adjustment. This technique works at any scale: 6-8-10, 9-12-15, or even 30-40-50 for large-scale work.
Navigation: Finding Straight-Line Distance
Suppose you walk 3 miles east and then 4 miles north. How far are you from your starting point “as the crow flies”?
Your path forms two legs of a right triangle. The straight-line distance back is the hypotenuse: $$d = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \text{ miles}$$
Pilots, sailors, and hikers use this principle constantly when calculating direct distances between points.
Ladder Safety
Safety guidelines recommend that a ladder be placed so that the distance from the wall is about one-quarter of the ladder’s length. For a 20-foot ladder, that means placing the base 5 feet from the wall.
How high up the wall does the ladder reach? $$h = \sqrt{20^2 - 5^2} = \sqrt{400 - 25} = \sqrt{375} \approx 19.4 \text{ feet}$$
The Pythagorean Theorem helps you calculate safe ladder placements and working heights.
Screen Diagonal Measurements
Television and monitor sizes are measured diagonally. If you know a TV is 48 inches wide and 27 inches tall, you can find its diagonal: $$d = \sqrt{48^2 + 27^2} = \sqrt{2304 + 729} = \sqrt{3033} \approx 55 \text{ inches}$$
This is why it is called a “55-inch TV” even though neither the width nor height is 55 inches.
Sports: Field Distances
In baseball, the distance from home plate to first base is 90 feet. The distance from home plate to second base (diagonally across the diamond) is: $$d = \sqrt{90^2 + 90^2} = \sqrt{8100 + 8100} = \sqrt{16200} = 90\sqrt{2} \approx 127.3 \text{ feet}$$
This is exactly the 45-45-90 relationship in action!
Self-Test Problems
Problem 1: A right triangle has legs of 9 and 12. Find the hypotenuse.
Show Answer
Use the Pythagorean Theorem: $$c^2 = 9^2 + 12^2 = 81 + 144 = 225$$ $$c = \sqrt{225} = 15$$
The hypotenuse is 15 (this is the 3-4-5 triple multiplied by 3).
Problem 2: A right triangle has a hypotenuse of 26 and one leg of 10. Find the other leg.
Show Answer
$$a^2 + 10^2 = 26^2$$ $$a^2 + 100 = 676$$ $$a^2 = 576$$ $$a = \sqrt{576} = 24$$
The other leg is 24 (this is the 5-12-13 triple multiplied by 2).
Problem 3: Determine whether a triangle with sides 5, 7, and 9 is right, acute, or obtuse.
Show Answer
The longest side is 9, so if this were a right triangle, 9 would be the hypotenuse.
Check: $5^2 + 7^2 = 25 + 49 = 74$
Compare to $9^2 = 81$
Since $74 < 81$, we have $a^2 + b^2 < c^2$.
The triangle is obtuse (the angle opposite the side of length 9 is greater than $90°$).
Problem 4: In a 45-45-90 triangle, each leg is 8 units. Find the hypotenuse.
Show Answer
In a 45-45-90 triangle, hypotenuse = leg $\times \sqrt{2}$
Hypotenuse $= 8\sqrt{2}$ units (approximately 11.31 units).
Verification: $8^2 + 8^2 = 64 + 64 = 128 = (8\sqrt{2})^2$
Problem 5: In a 30-60-90 triangle, the hypotenuse is 14. Find the lengths of both legs.
Show Answer
In a 30-60-90 triangle, hypotenuse $= 2x$, so: $$2x = 14$$ $$x = 7$$
- Shorter leg (opposite $30°$): $x = 7$ units
- Longer leg (opposite $60°$): $x\sqrt{3} = 7\sqrt{3} \approx 12.12$ units
Verification: $7^2 + (7\sqrt{3})^2 = 49 + 147 = 196 = 14^2$
Problem 6: A rectangular room is 15 feet by 20 feet. What is the length of the diagonal across the floor?
Show Answer
The diagonal forms the hypotenuse of a right triangle with legs 15 and 20: $$d = \sqrt{15^2 + 20^2} = \sqrt{225 + 400} = \sqrt{625} = 25 \text{ feet}$$
The diagonal is 25 feet (this is the 3-4-5 triple multiplied by 5).
Problem 7: A guy wire is attached to the top of a 40-foot pole and anchored to the ground 30 feet from the base. How long is the wire?
Show Answer
The pole, ground, and wire form a right triangle: $$\text{wire}^2 = 40^2 + 30^2 = 1600 + 900 = 2500$$ $$\text{wire} = \sqrt{2500} = 50 \text{ feet}$$
The guy wire is 50 feet long (this is the 3-4-5 triple multiplied by 10).
Summary
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A right triangle has one $90°$ angle. The two sides forming this angle are the legs ($a$ and $b$), and the side opposite the right angle is the hypotenuse ($c$), which is always the longest side.
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The Pythagorean Theorem states: $a^2 + b^2 = c^2$. This relationship holds for every right triangle and allows you to find any side when you know the other two.
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Pythagorean triples are sets of three positive integers that satisfy the theorem (3-4-5, 5-12-13, 8-15-17, etc.). Recognizing these can save you calculation time.
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The converse works too: if $a^2 + b^2 = c^2$ for a triangle’s sides, then the triangle must be a right triangle.
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You can classify triangles using this relationship:
- $a^2 + b^2 = c^2$: right triangle
- $a^2 + b^2 > c^2$: acute triangle
- $a^2 + b^2 < c^2$: obtuse triangle
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45-45-90 triangles have sides in the ratio $x : x : x\sqrt{2}$. They are isosceles right triangles, formed by cutting a square diagonally.
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30-60-90 triangles have sides in the ratio $x : x\sqrt{3} : 2x$. They come from cutting an equilateral triangle in half.
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The Pythagorean Theorem appears everywhere in real life: construction (checking square corners), navigation (finding direct distances), ladder safety calculations, screen measurements, and countless other applications.
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The geometric mean connects to right triangles through the altitude to the hypotenuse, creating proportional relationships useful in more advanced problems.
When you truly understand the Pythagorean Theorem and special right triangles, you have tools that will serve you well in trigonometry, physics, engineering, and everyday problem-solving. This 2,500-year-old theorem remains one of the most practically useful pieces of mathematics ever discovered.